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Chinese postman's problem: различия между версиями

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'''Chinese postman's problem''' --- задача китайского почтальона.  
'''Chinese postman's problem''' [[задача китайского почтальона]].  


Let <math>G = (V,E)</math> be a connected undirected graph. A non-negative cost (or length) is
Let <math>G = (V,E)</math> be a [[connected graph|connected]] [[graph, undirected graph, nonoriented graph|undirected graph]]. A non-negative cost (or length) is
associated with each edge of <math>G</math>. The '''Chinese postman's problem''' consists in
associated with each [[edge]] of <math>G</math>. The '''Chinese postman's problem''' consists in
determining a least-cost ''traversal'' of <math>G</math>.
determining a least-cost ''traversal'' of <math>G</math>.
==Литература==
* Евстигнеев В.А., Касьянов В.Н. Словарь по графам в информатике. — Новосибирск: Сибирское Научное Издательство, 2009.